Assuming there is no overpotential, Predict the products formed at the anode and cathode during the electrolysis of ZnCl2 in water?

standard cell potentials:

Cl2 + 2e- ---> 2Cl- Ecell=+1.36V
O2 +4H+ + 4e- ---> H20 Ecell=+0.82V
2H20 +2e- ---> 20H- + H2 Ecell=-0.42V
Zn^2+ + 2e- --->Zn Ecell=-0.76V

Choices:
a) Cl2 at the anode and Zn at the cathode
b) Cl2 at the anode and H2 at the cathode
c) O2 at the anode and Zn at the cathode
d)O2 at the anode and H2 at the cathode