To a flask containing 2L of water is added 1.3 x 10^-5 moles of an acid HA, that has a measured Ka of 5 x 10^-3. Assuming that the addition of the acid does not change the volume of the solution what is the pH of the acid/water mixture in the flask? Please show all of your work and steps on how you achieved the answer!
The acid dissociates according to this equation: HA --> H^+ (+) A^-