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A 42.60 gram sample of a hydrate of BaI2 was heated thoroughly in a porcelain crucible, until its weight remained constant. After heating, 39.01 grams of the dehydrated compound remained. What is the formula of the hydrate?
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Consider the following reaction: CO + H2 CH3OH A reaction mixture in a 5.18 L flask at a certain temperature contains 26.8 g CO and 2.36 g H2 . At equilibrium, the flask contains 8.67 g CH3OH. Calculate the equilibrium c ...
What is the density in g/mL of a ball that has a mass of 22.1 ounces and a diameter of 2.04 inches? Will it float if placed in a bucket of water? The answer is "no." Please can you help me Provide the calculations to pro ...
Insoluble PbBr2(s) precipitates when solutions of Pb(NO3)2(aq) and NaBr(aq) are mixed. Pb(NO3)2(aq) + 2NaBr(aq) ---> PbBr2(s) + 2NaNO3(aq) ΔrH = ? To measure the enthalpy change, 350. mL of 0.50 M Pb(NO3)2(aq) and 350. ...
Q1. Sodium metal is very active with water. Therefore, determining the value of a block of sodium will be impossible by water displacement. On the other hand, the density of sodium metal can be found in the chemistry han ...
What is the volume of a solution with a concentration of 1.2 M that contains 12 g of NaOH?
Calculate the boling point of a solution prepared by adding 11.5 g naphthalene (C10H8) to 250.0 g of benzene. Naphthalene is a non-electrolyte solute, and benzene is an organic solvent that exhibits a boiling point of 80 ...
Calculate volume in milliliters of a 1.96 mol/L calcium bromide solution that contains 275. mmol of calcium bromide CaBr2. Round your answer to 3 significant digits.
A 1.000 g sample of copper metal is heated in a crucible and after 15 minutes themass of the crucible contents is 1.111 g. Calculate the mass of copper (II) oxide that was produced.
What is the mass of NaOH present in grams, given that a 100. mL solution has a concentration of 0.125 M?
Use the simulator for the hydrogen atom (https://phet.colorado.edu/en/simulation/hydrogen-atom) to estimate the energy needed to transfer one mole of electrons from the energy level n = 1 to the level n = 3.
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