(Answered) An inductor designed with 400 turns coil wound on an iron

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An inductor designed with 400 turns coil wound on an iron core of 16 cm² cross sectional area and with a cut of an air gap length of 1 mm. The coil is connected to a 230 V, 50 Hz AC supply. Neglect coil resistance, core loss, iron reluctance and leakage inductance, (μ₀ = 4π × 10^-7 H/M)

The average force on the core to reduce the air gap will be?

n = 400 turns

cross-sectional area of coil is 16 cm²

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