An ice skater is spinning at 6.6 rev/s and has a moment of inertia of 0.32 kg*m2. f1= 6.6 rev/s f2= 0.75 rev/s f3= 3.75 rev/s I= 0.32 kg*m2 t= 12 s Angular momentum of ice skater spinning at 6.6 rev/s: 13.27

a) He reduces his rate of rotation by extending his arms and increasing his mo ment of inertia. Find the value of his moment of inertia (in kg*m2) if his rate of rotation decreases to 0.75 rev/s

b) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.75 rev/s. What is the magnitude of average torque that was exerted, in N*m if this takes 12 s?