An electron with a velocity of v 3x 4y 2z times 106 ms, Ask an Expert

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An electron with a velocity of v= (3x+ 4y+ 2z) × 10⁶ m/s enters a region where there is both a magnetic field and an electric field. The magnetic field is B = (1x- 2y+ 4z)T. If the electron experiences no force as it moves, calculate the electric field.

force of electric field is F=Eq

for of magnetic field is F=qV*B

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