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An electron has an initial velocity of 3.00 multiplied by 106 m/s in a uniform 10.0 multiplied by 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity.

(a) What is the direction of the electric field?

(b) How far does the electron travel before coming to rest?

(d) What is the electron's speed when it returns to its starting point?

m/s

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Reference No.:- M9893545

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