An electrochemical cell is constructed by coupling a Cu(II)/Cuhalf-cell with an Ag(I)/Ag half cell. The concentration of Cu(II)and Ag(I) are both 0.010 M. The observed potential ,E, is 0.40 v,with Cu at the anode. If Eo is 0.80 v for the half reaction: Ag(I)+ e- <==> Ag(s) find the value for Eo for the half reaction:Cu(II) + 2e- <===> Cu(s)