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Assume that a student places 1.0 mol of solid PbBr2 in 1.0 L of 0.0010 M Pb2+. Part of the lead bromide dissolves according to the following reaction...

PbBr2(s) ---> Pb2+(aq) + 2Br-(aq)

After allowing the solution to sit for 30 minutes the student determines that the bromide concentration was [Br-]= 0.0012 M. What is the Pb2+ concentration?

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