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A volume of 70.0 of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 13.2 of 1.50 was needed? The equation is
2KOH(aq)+H2SO4(aq)> K2SO4(aq)+2H2O(l)
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