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A volume of 70.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 18.2 mL of 1.50 M H2SO4 was needed? The equation is 2KOH+H2SO4K-->2SO4+2H2O
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What is the balanced equation? What is the calculation of the number of moles and grams of Al2(SO4)3 formed from 15.3 grams of H2SO4. Answering to 3 significant figures. Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
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1. Suppose 100.0 mL of an aqueous solution containing an unknown monoprotic acid (called HA) is titrated with 0.150 M KOH. The titration requires 47.82 mL of the potassium hydroxide to reach the equivalence point. What i ...
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