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A volume of 60.0 mL of aqueous potassium hydroxide(KOH)was titrated against a standard solution of sulfuric acid(H2SO4). What was the molarity of the KOH solution if 24.7 mL of 1.50M H2SO4 was needed? The equation is: 2KOH(aq)+H2SO4(aq)-->K2SO4(aq)+2H2O(l)

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