A tritium 3 1 h nucleus with kinetic energy of 470 mev is, Ask an Expert

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A Tritium (3 1 H) nucleus with kinetic energy of 4.70 MeV is incident on a stationary target of phosphorus (30 15 P); the nuclear reaction that results is written as: 3 1 H + 30 15 P -? 32 16 S + 1 0 n Some useful atomic masses are given as: Tritium 3 1 H = 3.016049 u Phosphorus 30 15 P = 29.978314 u Sulfur 32 16 S = 31.972071 u Neutron 1 0 n = 1.008665 u

a. Find the radius of the nucleus 32 16 S.

b. Find the nuclear binding energy of the nucleus 32 16 S (in MeV).

c. If we ignore the recoil of the 32 16 S nucleus, find the kinetic energy of the emitted neutron in MeV.

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