A thin uniformly chargde rod has a length L=10cm and a linear charge density lambda = +5x10^6 e/cm. e is the change of an electron, which equals to 1.6x10^-19 C. Given a=5cm (a is the distance on the x axis from the origin to the beginning of the horizontal rod length) and b=15cm (b is the distance along the y axis to point P) find the electric potential at the point P and Q. Hint: dq=(lambda)dx. The unit of electric potential is volt. It is joule per coulomb. K=8.99x10^9 Nxm^2/C^2.

If graphed, A would range from (0,0) to (5,0). B would range from (0,0) to (0,15). The length of rod would range from (5,0) to (15,0). Point P is located at (0,15) and Q is located at (15,15). The overall shape is a square.