A thermodynamic study of dycl3 determined its standard, Ask an Expert

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a thermodynamic study of DyCl3 determined its standard enthalpy of formation from the following information. Determine delta (subscript f) H for DyCl3 from the following reaction enthalpies

i) DyCl3 (s) ----> DyCl3 (aq in 4.9 M HCl) heat formation = 180.06 kJ/ mol

ii) Dy (s) + 3HCl(aq) ---> DyCl3 (aq) + 3/2 H2 (g) heat formation= -699.43 kJ/mol

iii) 1/2 H2 (g) + 1/2 Cl2(g) ----> HCl (aq) heat formation= -158.31 kJ

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