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A solution is made by dissolving 0.75 g of salt in 100.00 g of water. Calculate the % m/m for the solution. *0.74% m/m *0.75% m/m *7.5% m/m *7.4% m/m
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Suppose that you take .5000 gram of Na2CO3 and titrate it with .115M HCL solution. What is the equivalence point volume expected for the complete titration? (Formula weights Na2CO3 = 105.99g/mol and HCL = 36.46g/mol)
Assume that you dissolve 10.2 g of a mixture of NaOH and Ba(OH)2 in 227.0 mL of water and titrate with 1.47M hydrochloric acid. The titration is complete when 107.8 mL of the acid has been added. What is the mass (in gra ...
A sample consisting of 1.0 mol CaCO3(s) was heated to 800 °C, when it decomposed. The heating was carried out in a container fitted with a piston that was initially resting on the solid. Calculate the work done during co ...
At rest, a person inhales 9.72*10^21 nitrogen molecules in an average breath of air. How many mole of nitrogen atoms are inhaled? (Hint: in air, nitrogen occurs as a diatomic molecule)
Calculate the boling point of a solution prepared by adding 11.5 g naphthalene (C10H8) to 250.0 g of benzene. Naphthalene is a non-electrolyte solute, and benzene is an organic solvent that exhibits a boiling point of 80 ...
When 3.56 g of an unknown hydrocarbon was dissolved in 125 g of benzene, the freezing pointof the solution was found to be 4.41oC. Analysis of thehydrocarbon showed that it contained 93.71% carbon (by mass) and6.29% hydr ...
An analysis of an oxide of nitrogen with a molecular weight of92.02 amu gave 69.57% oxygen and 30.43 % nitrogen. What is the empirical formula of the compound?
While heating your copper sulfur mixture the original crucible lid fell and was broken. You replace the lid with another one. You used the mass of the original lid in your calculations. However the mass of the second lid ...
For the reaction 2CH4(g)?C2H2(g)+3H2(g) K = 0.170 at 1725 °C. What is K p for the reaction at this temperature? Express your answer numerically. For the reaction N2(g)+3H2(g)?2NH3(g) K p= 3.95×10 -3 at 325 °C . What i ...
Explain why the faster red particles in the video slow down and the slower blue particles speed up when they come into contact with each other.
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