A solid cylinder m2.15 kg r0.133 m pivots on a thin fixed, Ask an Expert

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A solid cylinder (M=2.15 kg, R=0.133 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.750 kg mass, i.e., F = 7.357 N. Calculate the angular acceleration of the cylinder.

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