(Answered) A single force acts on a 35 kg particle-like object in such

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A single force acts on a 3.5 kg particle-like object in such a way that the position of the object as a function of time is given by x = 1.6t - 4.2t² + 0.93t³, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 2.7 s.

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