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A rigid, sealed 1936 Ford coupe contains an equilibrium water liquid-vapor mixture with a quality of 8.8333% at 3.00 psia. After 500. Btu of heat energy are added to the coupe, the content becomes a saturated vapor. What is the total mass of water in the coupe? Fill in the following table (with correct units) and show all calculations. Unknown: m = unknown?

Helpful Hint: 1W2 = 0 (rigid vessel), T1 is found using pressure steam tables. Specific volume (v1) and internal energy (u1) are determined given the quality of the fluid-vapor mixture and the equation that relates to them. Since this is a rigid vessel, v2 = v1. State 2 is saturated vapor, the value for v2 can be used to specify p2, T2, and u2 using the pressure steam tables. Solve for m using the modified EB expression (ke and pe terms drop out).

Please show ALL work!

Process = unknown? / 1Q2 = 500 Btu

State 1

p1 = 3.00 psia

x1 = 0.088333

v1 = unknown?

T1 = unknown?

State 2

p2 = unknown?

x2 = 1.00

v2 = unknown?

T2 = unknown?

u2 = unknown?

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  • Category:- Physics
  • Reference No.:- M9962188

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