A peice of gold 10.0-g c of au 0.129 jg-k is heated to, Ask an Expert

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A peice of gold (10.0-g, C of Au = 0.129 J/g-K) is heated to 100.0 degrees Celcius. A peice of copper (also 10.0-g C of Cu = 0.385 J/g-K) is chilled in an ice bath to 0 degrees Celcius. Both peices of metal are placed in a beaker containing 150. -g H2O at 20 degrees Celcius. Will the temp of the water be greater than or less than 20 degrees when thermal equilibrium is eached? Calculate the final temp.

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Category:- Chemistry
Reference No.:- M9460471

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