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A parallel-plate capacitor has plates of area 114.0 cm2 and a separation of 1.45 cm. A battery charges the plates to a potential difference of 177.0 V and is then disconnected. A dielectric slab of thickness 5.37 mm and dielectric constant 6.50 is then placed symmetrically between the plates.

Find the capacitance before the slab is inserted.

What is the capacitance with the slab in place?

What is the free charge (charge on a plate) before the slab is inserted?

What is the free charge after the slab is inserted?

What is the magnitude of the electric field in the space between the plates and dielectric?

With the slab in place, what is the potential difference across the plates? What is the magnitude of the electric field in the dielectric?

What is the magnitude of the external work involved in the process of inserting the slab?

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  • Category:- Physics
  • Reference No.:- M9904881

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