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A nucleus of the boron-11 isotope consists of five protons and six neutrons. A particular ionized atom of boron-11, whose mass is 1.83 × 10-26 kg, lacks 5 electrons from its neutral state. Find the magnitude and direction of the electric field that will levitate this ion, exactly balancing its weight. Take g = 9.81 m/s2. Magnitude: Direction:

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