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A mortar crew is positioned near the top of a steep hill. Enemy forces are charging up the hill and it is necessary for the crew to spring into action. Angling the mortar at an angle of ? = 49.0o (as shown), the crew fires the shell at a muzzle velocity of 202 feet per second. How far down the hill does the shell strike if the hill subtends an angle ? = 35.0o from the horizontal? (Ignore air friction.) How long will the mortar shell remain in the air? How fast will the shell be traveling when it hits the ground?

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