A metal, M, was converted to the chloride, MCl2. Then a solution of the chloride was treated with silver nitrate to give silver chloride crystals, which were filtered from the solution.
MCl2(aq) + 2 AgNo3(aq) --> M(NO3)2(aq) + 2 AgCl(s)
If 2.434 g of the metal 7.964 g of silver chloride, what is the atomic number of the metal? What is the metal?