(Answered) A flask contains a 03437 m solution of potassium hydroxide

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A flask contains a 0.3437 M solution of potassium hydroxide. The solution is titrated and reaches an equivalence point when 21.65 m L of a 0.6515M solution of HNO₃ is added. Calculate the volume of the base solution:

HNO₃ +KOH ----> KNO₃ +HOH

A H₂SO₄ solution of unknown molarity is titrated with 1.209 M NaOH solution. The titration requries 42.27 mL of the NaOH solution to reach the equivalent point with 25.00mL of the H₂SO₄ solution. What is the molarity of the acid solution?

2NaOH +H₂SO₄----> Na₂SO₄ + 2HOH

Please show work.

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