A charge of 650 multiplied by 10-9 c and a charge of -250, Ask an Expert

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A charge of 6.50 multiplied by 10^-9 C and a charge of -2.50 multiplied by 10^-9C are separated by a distance of 60.0 cm. Find the position at which a third charge, of 10.0 multiplied by 10^-9C, can be placed so that the net electrostatic force on it is zero.

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