A catapult throws a projectile at a castle but it lands 500, Ask an Expert

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A catapult throws a projectile at a castle, but it lands 5.00 m short of the castle wall. The position of the projectile as a function of time is given by the equation

r^→(t) =(21.7m/s)t i^ + [(12.5m/s)t - (4.90m/s²)t2]j^.

1) What is the average velocity of this projectile for the first 2.00 s of flight?

2) At what time is the y-component of the projectile's velocity zero?

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Category:- Physics
Reference No.:- M91709530

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