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A capacitor is charged to an initial voltage V0 = 25.5 V. The capacitor is the discharged by connecting its terminals through a resistor. The current I(t) through this resistor, determined by measuring the voltage VR(t) = I(t)R with an oscilloscope, is shown in the graph, in which each division on the horizontal axis equals 4 ms.

2282_determined by measuring the voltage with an oscilloscope.gif

(a) Find the capacitance C, the resistance R, and the total energy dissipated in the resistor.

(b) At what time is the energy in the capacitor half its initial value?

(c) Graph the voltage across the capacitor, VC (t), as a function of time.

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