A calculate g and kp for the following equibibrium reaction, Ask an Expert

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a) Calculate ?G' and Kp for the following equibibrium reaction at 25'C/ The ?Gf' values are 0 for Cl2(g), -286 kJ/mol for PCl3(g), and -325 kJ/mol for PCl5(g).

b) calculate ?G for the reaction if the partial pressures of the initial mixture are PPCl5 = 0.0029 atm, PPCl3 = 0.27 atm, and PCl2 = 0.40 atm ( Kp = e-?G'/RT where R = 8.314 J/K mol. Hint part B: Find the Qp) PCl5(g) <---> PCl3(g) + Cl2(g)

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