A basketball star covers 2.85 m horizontally in a jump to dunk the ball (see figure below left). His motion through space can be modeled precisely as that of a particle at his center of mass. His center of mass is at elevation 1.06 m when he leaves the floor. It reaches a maximum height of 1.90 m above the floor and is at elevation 0.870 m when he touches down again. (Take the upward and forward directions to be positive.)

(a) Determine his time of flight (his "hang time").

(b) Determine his horizontal velocity at the instant of takeoff. (Indicate the direction with the sign of your answer.)

(c) Determine his vertical velocity at the instant of takeoff. (Indicate the direction with the sign of your answer.)

(d) Determine his takeoff angle° above the horizontal.