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A 500 mg sample containing NaCn required 23.50 ml of 0.1255 M AgNO3 to obtain a permanent faint turbidity. Express the result of this analysis as % CN ?
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2K3PO4(aq)+3MgCl2(aq) → Mg3(PO4)2(s)+6KCl(aq) The molecular equation you determined in Part B is shown above for your convenience. Examine each of the chemical species involved to determine the ions that would be present ...
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