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A 125g metal block at a temperature of 93.2 degrees Celsius was immersed in 100g of water at 18.3 degrees celsius. Given the specific heat of metal (s= 0.900j/g x degrees celsius), find the final temperature of the block and the water.
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What is the balanced equation? What is the calculation of the number of moles and grams of Al2(SO4)3 formed from 15.3 grams of H2SO4. Answering to 3 significant figures. Al(OH)3 + H2SO4 → Al2(SO4)3 + H2O
A student takes 5.0mL of a stock FeSCN2+ solution and dilutes it with deionized water to a volume of 50mL. He then puts the solution in a Spectronic 20 instrument and determines the the % transmittance of the new solutio ...
Over the next 12 months Bradley Metals (Located in Vancouver) will order aprox. 6000 of forging units (from Kurrat Tools, located in Montreal) with the average weight of 15 LBS/unit.(6000/12= 500 units per month). 6,00 ...
What is the differene between sodium chloride versus sodium chlorite
C-14 analysis of the Shroud of Turin has shown that approximately 93% of the 14C present in living matter is still present in samples taken from the shroud. Based on this information, what is the approximate age of this ...
A student weighed out 1.74 grams of sodium hydroxide pellets andadded them to 48.0 grams of water in a calorimeter. Extrapolatingback to the time of mixing yielded a temperature change at the timeof mixing equal to 9.20 ...
Determine if the reactants shown on the right would result in the formation of a precipitate. Choices can be used more than one time or not at all. Forms a precipitate Will not form a precipitate Na 2 SO 4 + Ba(NO 3 ) 2 ...
A mass of 8.15 gC 2 H 4 ( g ) reacts with excess oxygen. If 16.2 g CO 2 ( g ) is collected, what is the percent yield of the reaction? C 2 H 4 ( g ) + 3O 2 ( g )® 2CO 2 ( g ) +2H 2 O( g )
A 43 kg person drinks 430 g of milk, which has a "caloric" value ofapproximately 3.0 kJ/g. If only 15% ofthe energy in milk is converted to mechanical work, how high (inmeters) can the person climb based on this energy i ...
A chemist must dilute 37.4 mL of 8.08 μM aqueous mercury(I) chloride (Hg2Cl2) solution until the concentration falls to 2.00 μM. He'll do this by adding distilled water to the solution until it reaches a certain final vo ...
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