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A 100.0 g copper sample (specific heat = 0.385 J/goC) at 100.0oC is added to 50.0 g water at 26.5oC. What is the final temperature of the copper-water mixture?
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You will have a 500mL solution of salt water. From this you will take 10.0mL and place it on a balance. You find that the 10.0mL solution has a mass of 12.5 g. What is the density of the 500mL of salt water solution in g ...
A photon of wavelength 200 nm strikes the surface of a metal causing an electron to be ejected with kinetic energy of 4.3 x 10-19 J. What was the threshold frequency of the metal?
A 3.15- sample of NH4NO3 is introduced intoan evacuated 2.26- L flask and then heated to 245 C. What is the total gas pressure, in atmospheres, in the flask at245 C when the NH4NO3 has completely decomposed?
Over the next 12 months Bradley Metals (Located in Vancouver) will order aprox. 6000 of forging units (from Kurrat Tools, located in Montreal) with the average weight of 15 LBS/unit.(6000/12= 500 units per month). 6,00 ...
Calculate volume in milliliters of a 1.96 mol/L calcium bromide solution that contains 275. mmol of calcium bromide CaBr2. Round your answer to 3 significant digits.
Why do the instructions call for using a saturated solution of NaOH rather than one at lower concentration? Why can we ignored in the calculation of the concentration of NaOH?
A chemist must prepare 725. mL of 275. mM aqueous copper(II) sulfate CuSO4 working solution. He'll do this by pouring out some 0.316 M aqueous copper(II) sulfate stock solution into a graduated cylinder and diluting it w ...
What are the benefits of measuring the absorbance at the maximum absorbance wavelength? If light has a wavelength of 756 nm, what is the wavelength in centimeters? What is the wavelength in inches?
Give an example of when heat is released from water as it undergoes a change of phase.
1.00 mole of sodium carbonate (formula mass 106.0) is converted to sodium chloride, Na2CO3(s) + 2HCl(aq)® 2NaCl(aq) + H2O +CO2(g). The percentage yield in this conversion is 80%.Which of the following is correct: a. 0.80 ...
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