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A particle is projected from ground with velocity 40sqrt2m/s.find- a)velocity and b)displacement of particle after 2sec .Take g=10m/s^2 Ans)velocityv=u+ata=-gv=40√2-10*2v=20(2√2-1)m/ss=ut+at2/2s=40√2*2-10*2*2s=80√2-40s=40(2√2-1)m
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