150 ml of a 0100 m solution of malonic acid is titrated, Ask an Expert

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15.0 mL of a 0.100 M solution of malonic acid is titrated with 0.109 M NaOH.
Ka1 = 1.5 x 10^-3
Ka2 = 2.0 x 10^-6

a) What is the pH when 5.00 mL of base has been added?

b) What volume is required to get to the first midpoint (midpoint of the buffer region)?

c) What is the pH at the first and second midpoints?

d) What is the pH at the first equivalence point?

e) What is the pH at the second equivalence point?

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Category:- Chemistry
Reference No.:- M91080915

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