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- Why is I2 the limiting reactant in the form of SnI2 (hint: look at the redox potentials for all possible reactions.

- And why use concentrated HCl in the reaction(hint: look at what happens when tin reacts with aq HCL to form the SnCl2 and what happens to SnCl2 in solution--what is ratio of Cl- to Sn, look at solubility, etc)

Sn + 2I2------>SnI4

Zn(s) + I2(s) -----> Zn^2+ (aq) + 2I^- (aq)

Sn(s)+2HCl (aq) -----> Sn^2+ (aq) +2Cl- (aq) + H2 (g)

Sn2+ (aq) + 2I- (aq) -----> SnI2 (s)

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