Programming in C:
Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".
#include
#include
int main(void) {
double targetValue = 0.3333;
double sensorReading = 0.0;
sensorReading = 1.0/3.0;
if (/* Your solution goes here */) {
printf("Equal\n");
}
else {
printf("Not equal\n");
}
return 0;
}