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Problem:

Consider a relation R(A, B, C, D, E, F), with FDs AB → C , BC → D, D → E, BE → F and DF → C.

1. Is R in BCNF? Explain why or why not.

2. Find the closure of the following:

1. (A, B) 
2. (B, D) 
3. (D, F)

3. List one superkey of R that is not a (minimal) key.

Additional Information:

This question is from Computer Science and it is about determining whether or not a relation comes under BCNF (Boyce-Codd Normal Form) or not. This has been given in the solution comprehensively.

Computer Engineering, Engineering

  • Category:- Computer Engineering
  • Reference No.:- M91399361
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