A quick explanation of the game; you bet $1 on a number 1-6 and roll 3 dice. You get back how ever many of that number turn up (example, you bet '3', and it shows up twice, you get $2 back), you lose if you number doesn't show. In this version, there are C(6+3-1,3) = 56 different outcomes in Chuck-a-Luck. Order doesn't matter, just the number's that come up. Out of those 56, how many outcomes have at least one 1?