In a two stage network there are 512 inlets and outlets, Ask an Expert

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In a two stage network there are 512 inlets and outlets, r=s=24. If the probability that a given inlet is active is 0.8, calculate: Blocking probability

Given:

N =M =512,

α =0.8,

r=s=24

Therefore Blocking Probability

PB = (M α (s-1)-((M/r-1)) α)/(rs(s-1))

= (512 x 0.8(23) - (512/24-1)0.8)/( 24 x 24 (23))

= 0.7

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Computer Engineering, Engineering

Category:- Computer Engineering
Reference No.:- M9548180

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