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Example 3: Travelling Salesman problem

Given: n associated cities and distances among them

Find: tour of minimum length that visits all of city.

Solutions: How several tours are possible?

n*(n -1)...*1 = n!

Because  n! > 2(n-1)

Therefore n! = ? (2n) (lower bound)

As of now, there is no algorithm that determines a tour of minimum length plus covers all of the cities in polynomial time.  But, there are many very good heuristic algorithms.

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  • Category:- Computer Engineering
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