A pure shear deformation is applied to the square element as shown in the figure such that σ₁₂ = σ₂₁ is only nonzero stress component.

At load step n, the stress value was σ₁₂ = 50, and there was no plastic deformation. At load step n + 1, incremental strain Δε₁₂ = Δε₂₁ = 0.005 is applied. Calculate stress components andeffective plastic strainatload step n + 1.

Use the following material properties: shear modulus μ = 1,000, plastic modulus H = 100, initial yield stress σ_Y = 100.