(Answered) The original table isnbspstu-maj-adv sid fid majorfd

Management Studies

The original table is

STU-Maj-Adv (SID, FID, Major)

FD: FID Major (each faculty specializes only one major)

(SID, Major) and (SID, FID) are all candidate keys (CK)

assuming a student can have multiple majors. A student can only have one faculty as his/her advisor for the major he/she chose.

an student normalized the following table and he/she got three solutions (a, b . c). Only one of them is correct. Identify the correct solution (note, fid is the ID of faculty advisor, sid is ID of student)

and give a detailed explanation of your choice.

a sm(sid, major), fm(fid,major)

b sm(sid, major), fs(fid, sid)

c fm(fid, major), fs(fid, sid)

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