(Answered) For a normal distribution with a mean of 158 and a standard

Management Studies

For a normal distribution with a mean of 158 and a standard deviation of 33, what is the Z value (distance from the mean) for a random value to be 148? z = (x - μ) / σ x value 148 mean 158 stand deviation 33 (x-mean)/stdev (148-158)/33 -0.30303 -0.30303 -0.30303

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