(Answered) We have an unfair die where any even number is twice as

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We have an unfair die where any even number is twice as likely as any odd number. So a, 2, 4, and 6 are all equally likely, and 1, 3, and 5 are all equally likely, but 2 is twice as likely as a 3, and so on. Find the probabilities of all the simple events

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