Toss 2 dice, and let the event be the sum of the values of the top faces. Because there are 36 outcomes, the probability of a sum =frequency of the sum/36. So the probabilities of the sums are SumPprobability

2 1/36

3 2/36

4 3/36

5 4/36

6 5/36

7 6/36

8 5/36

9 4/36

10 3/36

11 2/36

12 1/36

Only one of the sums 2 through 12 can occur in a single toss of the dice. These are mutually exclusive events. The Simple Addition Rule P(A or B)=P(A) + P(B applies).

Match the items on the left with the items on the right based on the above information.

1. 0.583 a. P(X at least 7)
2. 0.889 b. P(X is not 9)
3. 0.000 c. P(X=1)