To decide whether two different types of steel have the same true average fracture toughness values, n specimens of each type are tested, yielding the following results.
| Type | Sample Average | Sample SD |
| 1 |
60.9 |
1.0 |
| 2 |
60.7 |
1.0 |
Calculate the P-value for the appropriate two-sample z test, assuming that the data was based on n = 100. (Round your answer to four decimal places.)
Calculate the P-value for the appropriate two-sample z test, assuming that the data was based on n = 500. (Round your answer to four decimal places.)
Is the small P-value for n = 500 indicative of a difference that has practical significance? Would you have been satisfied with just a report of the P-value? Comment briefly.