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The width of a slot of a duralumin forging is (in inches) normally distributed with µ = 0.9000 and ? = 0.0030. The specification limits were given as 0.9000 ±0.0050.

a) What percentage of forgings will be defective?

b) What is the maximum allowable value of ? that will permit no more than 1 in 100 defectives when the widths are normally distributed with µ = 0.9000 and ? (revised value)?

Statistics and Probability, Statistics

  • Category:- Statistics and Probability
  • Reference No.:- M9991683

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