Chi-square test for independence of attributes.
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|
Column1
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Column2
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Column3
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Column4
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Column5
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1st shift hourly
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1st shift salary
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2nd shift hourly
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3rd shift hourly
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Total
|
|
Supervisor listens to employee
|
34
|
12
|
8
|
13
|
67
|
|
Supervisor does not listen to employee
|
16
|
3
|
10
|
4
|
33
|
|
Good working environment
|
31
|
11
|
6
|
9
|
57
|
|
Poor working environment
|
19
|
4
|
12
|
8
|
43
|
|
Opportunity for advancement
|
32
|
13
|
8
|
7
|
60
|
|
Lack of opportunity for advancement
|
18
|
2
|
10
|
10
|
40
|
|
Employee feels appreciated
|
33
|
12
|
9
|
8
|
62
|
|
Employee does not feel appreciated
|
17
|
3
|
9
|
9
|
38
|
The stable above is an entire population sample of 100 employees
The null hypothesis is H0: there is no difference in the results between the shifts.
Alternate hypothesis is H1: there is a difference in the results between the shifts
1. With the table above, what is the best Test statistic to use from the following?
Chi-square
Z-test
T-test
Analysis of Variance (ANOVA
Regression
Describe your reason for choosing the test statistic you chose
2. With the test statistic you chose, work out the problem with solution using .05 level of significance if it applies