Let  ./{x) = !, x = 1, 2, 3, 4, 5, 6,  zero  elsewhere, be the p.d.f. of a distribution of the discrete type. Show that the p.d.f. of the smallest observation of a random sample of size 5 from this distribution is gl(yl) = (7 -6 Y•)s -(6 -6 Y•)s, , y, = 1, 2, . . . , 6, zero elsewhere. Note that in this exercise the random sample is from a distribution of the discrete type. All formulas in the text were derived under the 'assumption that the random sample islrrom a distributioh of the continuous  type and are not  applicable.  Why?